Timeline for Necessary and sufficient conditions for the Cayley graph to be bipartite
Current License: CC BY-SA 4.0
12 events
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May 14 at 6:06 | comment | added | lunch zheng | I get it, by the way, I would like to ask, which book is this theorem from?(The Cayley graph is bipartite) | |
May 5 at 9:36 | comment | added | Corentin B | In order to have a proper coloring, we need $\pi(gs)\ne\pi(g)$ hence $\pi(gs)=\pi(g)+1=\pi(g)+\pi(s)$ for all $g\in G$ and $s\in S$. When the target group is $\mathbb Z/2\mathbb Z$, this is equivalent to $\pi$ being an homomorphism. | |
May 5 at 8:55 | comment | added | lunch zheng | Thank you, and why is it required here that $\pi$ is a homomorphism? | |
May 5 at 5:07 | vote | accept | lunch zheng | ||
May 5 at 5:07 | vote | accept | lunch zheng | ||
May 5 at 5:07 | |||||
May 4 at 14:05 | comment | added | Corentin B | @lunch zheng On which topics? Cayley graphs? I guess any book on geometric group theory will cover this (with more or less examples). I guess my favorites are "Offices Hours with Geometric Group Theorist" and "Topics in geometric group theory" (which I legally binded to promote, being in Geneva). | |
May 4 at 5:46 | comment | added | lunch zheng | Thank you for your response. Are there any related books or papers that introduce these topics, especially for specific groups? | |
May 2 at 16:37 | history | edited | Christopher King | CC BY-SA 4.0 |
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May 2 at 10:49 | history | edited | Emil Jeřábek | CC BY-SA 4.0 |
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May 2 at 8:15 | history | edited | Corentin B | CC BY-SA 4.0 |
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May 2 at 8:09 | history | edited | Corentin B | CC BY-SA 4.0 |
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May 2 at 8:07 | history | answered | Corentin B | CC BY-SA 4.0 |