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May 1 at 10:44 comment added Z. M No, the left adjoint is $\DeclareMathOperator\An{An}\An\DeclareMathOperator\CAlg{CAlg}\DeclareMathOperator\cn{cn}\DeclareMathOperator\an{an}\to\CAlg_R^{\an}\to\CAlg_R^{E_\infty,\cn}$ which carries a finite set to the polynomial $R$-algebra generated by this finite set and then to the free $E_\infty$-$R$-algebra generated by this finite set.
May 1 at 10:41 comment added Y.M So it should be the left adjoint takes free $E_{\infty}$-$R$-algebras to poly $R$-algebras?
May 1 at 10:34 comment added Z. M @Y.M The left adjoint carries free objects to free objects: consider taking left adjoints of the forgetful functor from animated rings to connective $E_\infty$-rings and then to anima.
May 1 at 10:16 comment added Y.M Thanks for the answer. In the proof of Prop 1, what do you mean by saying the left adjoint carries poly $R$-algebras to free $E_{\infty}$-$R$-algebras? My original concern is how to compare $Map(A,B)$ and $Map(A,\Theta(B))$ with $A$ a discrete $R$-algebra and $B$ an animated $R$-algebra. So I guess there is no general way to compare them?
May 1 at 9:04 history answered Z. M CC BY-SA 4.0