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when toggle format what by license comment
Jul 27, 2022 at 10:04 history edited Glorfindel CC BY-SA 4.0
broken link fixed, cf. https://math.meta.stackexchange.com/a/34713/228959
Nov 23, 2010 at 7:21 vote accept user7028
Nov 22, 2010 at 21:41 comment added José Figueroa-O'Farrill A hyperkähler manifold is Ricci-flat Kähler in a variety of ways -- that variety being $\mathbb{CP}^1$.
Nov 22, 2010 at 18:27 comment added user7028 Okay, I thought this... If someone is hyperkähler, is this Ricci-flat Kähler, too? What I mean: What is the connection between hyperkähler and Ricci-flat Kähler? Thanks!
Nov 22, 2010 at 18:21 history answered José Figueroa-O'Farrill CC BY-SA 2.5