Timeline for $n$-th derivative of $\exp\left(-\frac{\lambda(x-\mu)^2}{2\mu^2x}\right)$

14 events

when toggle format	what		by	license	comment
Apr 24 at 17:27	answer	added	Ira Gessel		timeline score: 4
Apr 23 at 12:41	answer	added	qifeng618		timeline score: 2
Apr 23 at 9:29	answer	added	qifeng618		timeline score: 0
Apr 22 at 21:18	answer	added	Iosif Pinelis		timeline score: 5
Apr 22 at 9:13	answer	added	Fred Hucht		timeline score: 6
Apr 21 at 16:42	answer	added	qifeng618		timeline score: 4
Apr 21 at 16:21	answer	added	Steven Clark		timeline score: 2
Apr 21 at 15:23	vote	accept	NancyBoy
Apr 21 at 11:41	review	Close votes
Apr 28 at 3:06
Apr 21 at 4:07	comment	added	მამუკა ჯიბლაძე		Not sure how to use it but changing the variable to $t=\sqrt{\frac\lambda{2x}}\left(1-\frac x\mu\right)$ should presumably give expressions through Hermite polynomials in $t$
Apr 21 at 3:16	answer	added	Iosif Pinelis		timeline score: 9
Apr 21 at 1:04	comment	added	Gerald Edgar		Of course $P_{\lambda, \mu}(x)$ also depends on $n$. For $n=3$, $$P_{\lambda, \mu}(x) =-8\,{\lambda}^{3}{x}^{6}+24\,{\lambda}^{3}{\mu}^{2}{x}^{4}+96\,{ \lambda}^{2}{\mu}^{4}{x}^{3}-8\,\lambda\, \left( 3\,{\lambda}^{2}{\mu} ^{4}-24\,{\mu}^{6} \right) {x}^{2}-96\,{\lambda}^{2}{\mu}^{6}x+8\,{ \lambda}^{3}{\mu}^{6}$$
Apr 20 at 18:33	history	edited	Daniel Asimov	CC BY-SA 4.0	spelling
Apr 20 at 10:07	history	asked	NancyBoy	CC BY-SA 4.0