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Apr 21 at 0:07 comment added Saúl RM @KhashF those sets are not measurable
Apr 20 at 22:58 comment added KhashF If the map from your counter example is to be measure preserving, all subsets $\{i\}\times S^1 \,(i\in\Bbb{Z})$ must have the same measure . But their measures must add up to $\mu(\Bbb{Z}\times S^1)=1$.
Apr 20 at 21:49 comment added Saúl RM Thanks for catching that, I added it explicitly
Apr 20 at 21:48 history edited Saúl RM CC BY-SA 4.0
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Apr 20 at 21:19 comment added KhashF @SaúlRM What is the probability measure in your counter example?
Apr 20 at 21:04 history edited Saúl RM CC BY-SA 4.0
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Apr 20 at 19:37 vote accept abcdmath
Apr 20 at 19:41
Apr 20 at 12:30 history edited Saúl RM CC BY-SA 4.0
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Apr 20 at 12:25 comment added Saúl RM Yes, I added a more detailed explanation
Apr 20 at 12:25 history edited Saúl RM CC BY-SA 4.0
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Apr 20 at 10:24 comment added abcdmath thank you.But could you please explain the last line of the second-to-last paragraph? that is, how $\mu(\bigcup_{i,j} T^{-kj}A\Delta T^{-ki}A)=0$ and also with $B_n$ and from there how can we assume $T^{-k}A=A$ and $T^{-k}B_n=B_n$?
Apr 19 at 21:45 history edited Saúl RM CC BY-SA 4.0
fixed typo
Apr 19 at 21:04 history answered Saúl RM CC BY-SA 4.0