Timeline for If matrices $A$ and $B$ are normal with $\sigma(A),\sigma(B)\subseteq \mathbb{R}\cup \mathbb{T}$, does $\text{rank}([A,B])=\text{rank}([A^*,B])$?
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 19 at 21:47 | comment | converted from answer | mathemagician99 | I also asked the question on math.se and it has been answered. | |
| Apr 18 at 12:20 | comment | added | mathemagician99 | @FedorPetrov No, maybe it is not even needed. The idea was to use this splitting into a self-adjoint and a unitary matrix. | |
| Apr 18 at 12:19 | history | edited | mathemagician99 | CC BY-SA 4.0 |
added 1 character in body
|
| Apr 18 at 12:17 | comment | added | Fedor Petrov | Do you have a counterexample when $A, B$ are just normal? | |
| Apr 18 at 12:00 | history | edited | mathemagician99 | CC BY-SA 4.0 |
added 95 characters in body
|
| Apr 18 at 11:59 | comment | added | mathemagician99 | @I.Haage The unit circle in the complex numbers. I will edit the question. | |
| Apr 18 at 11:58 | comment | added | I. Haage | what is $\mathbb{T}$? | |
| Apr 18 at 11:44 | history | edited | mathemagician99 | CC BY-SA 4.0 |
added 1 character in body
|
| Apr 18 at 11:36 | history | asked | mathemagician99 | CC BY-SA 4.0 |