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Peter Wu
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Here is a construction with $o(1/k)$$\Omega(1/k)$ fraction: consider $x_1x_2+x_3x_4+\dots \mod p$. In which $p$ is a prime larger than $k$. If two vertices are adjacent, their difference is $(b-c)(a-d)$, which is not divided by $p$. Thus one can take the largest residue class.

Here is a construction with $o(1/k)$ fraction: consider $x_1x_2+x_3x_4+\dots \mod p$. In which $p$ is a prime larger than $k$. If two vertices are adjacent, their difference is $(b-c)(a-d)$, which is not divided by $p$. Thus one can take the largest residue class.

Here is a construction with $\Omega(1/k)$ fraction: consider $x_1x_2+x_3x_4+\dots \mod p$. In which $p$ is a prime larger than $k$. If two vertices are adjacent, their difference is $(b-c)(a-d)$, which is not divided by $p$. Thus one can take the largest residue class.

Source Link
Peter Wu
  • 301
  • 1
  • 9

Here is a construction with $o(1/k)$ fraction: consider $x_1x_2+x_3x_4+\dots \mod p$. In which $p$ is a prime larger than $k$. If two vertices are adjacent, their difference is $(b-c)(a-d)$, which is not divided by $p$. Thus one can take the largest residue class.