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Nov 17, 2009 at 7:13 vote accept Casebash
Nov 9, 2009 at 15:49 comment added Greg Kuperberg Once you establish that the group algebra $\mathbb{C}[G]$ is a direct sum of matrix blocks, the irreducible representations are in 1-to-1 correspondence with the blocks. Then the easiest way to answer the counting question is to observe that both the conjugacy classes and the matrix blocks give you a basis of the center $Z(\mathbb{C}[G])$. Two bases of a vector space must have the same cardinality.
Nov 8, 2009 at 23:02 history answered javier CC BY-SA 2.5