Timeline for Equating two Fourier Series with different periods
Current License: CC BY-SA 4.0
2 events
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| Apr 12 at 14:52 | comment | added | Willie Wong | Certainly the implication starting from $g_k \neq 0$ is not true. Just take any $g$ supported in $(\tau,1)$. Certainly $g_k$ is not identically zero for all $k$. But $f_k$ must be all zero. // In fact, even in the case $1/\tau\in \mathbb{Z}$ your conclusion is wrong. What you claim about $g_k$ would make $\tau$ a period of $g$. Certainly "$g_r = 0$ else" is incorrect. | |
| Apr 12 at 14:21 | history | asked | Martin | CC BY-SA 4.0 |