Timeline for Pullback morphism of a hyperplane inclusion is zero in the derived category
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
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| Apr 11 at 13:23 | comment | added | Phil Tosteson | @Eduardo If the homology of a complex is concentrated in a single degree, then you can always get an isomorphism with its homology group in the derived category. First you truncate the complex from above, and then you truncate the complex from below. | |
| Apr 11 at 13:17 | vote | accept | Eduardo de Lorenzo | ||
| Apr 11 at 13:16 | comment | added | Eduardo de Lorenzo | I see, so my problem was that I didn't know that $R\Gamma_c \underline{\mathbb{Z}}_{\mathbb{C^n}} = \mathbb{Z}[-2n]$. Is this hard to show? I was thinking of it as some weird injective resolution that I knew nothing about. | |
| Apr 11 at 12:52 | history | answered | Phil Tosteson | CC BY-SA 4.0 |