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Apr 11 at 6:24 history edited YCor CC BY-SA 4.0
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Apr 10 at 23:41 comment added Kenta Suzuki To elaborate on YCor's comment: $1\to Z(k^{sep})\to G(k^{sep})\to G^{ad}(k^{sep})\to 1$ is an exact sequence, and taking $\mathrm{Gal}(k^{sep}/k)$-fixed points is a left exact functor.
Apr 10 at 21:48 comment added YCor For $k$ algebraically closed it's a bijection (I guess, essentially by definition of quotient). Injectivity follows for arbitrary fields.
Apr 10 at 21:34 history edited Μάρκος Καραμέρης CC BY-SA 4.0
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Apr 10 at 21:29 history asked Μάρκος Καραμέρης CC BY-SA 4.0