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Oct 12 at 12:45 comment added მამუკა ჯიბლაძე Even without assuming $\Box\mathrm{true}=\mathrm{true}$ - I believe Bénabou was first to observe that the only $\Box:\Omega\to\Omega$ satisfying $\Box x\leqslant x$ are of the form $x\land\Box\mathrm{true}$. Indeed for any $\Box$ whatsoever, from $x\Rightarrow(x=\mathrm{true})$ it follows $x\land\Box x=x\land\Box\mathrm{true}$, so that if $\Box x\leqslant x$ then $\Box x=x\land\Box\mathrm{true}$.
Apr 14 at 14:28 vote accept Miviska
Apr 10 at 22:32 comment added Simon Henry [...] fine, but the kind of operator like the necessity and possibility that people doing modal logic are interested in aren't - at least not with this kind of naive interpretation.
Apr 10 at 22:31 comment added Simon Henry I'm not really an expert on all the form of Modal logic that exists so I can't really comment on that beyond "that's the kind of property a Neccessity operator is generally required to satisfies" if your modality operator don't satisfies that, maybe you should give it another name. I can't give you a blanket statement that no kind of modality operator is definable : as Mentioned by Gro-tsen Lawvere Tierney Topologies are something we may want to think as a modal operator and are perfectly fine and interesting internally in toposes. The sort of thing people in HoTT call modalities are also[...]
Apr 10 at 21:24 comment added Miviska Thank you so much for your answer! It is more clear now! However, why do we need to assume that for all $x \in \Omega, \Box x \leq x$?
Apr 10 at 19:37 history edited LSpice CC BY-SA 4.0
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Apr 10 at 15:35 history edited Simon Henry CC BY-SA 4.0
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Apr 10 at 14:31 history answered Simon Henry CC BY-SA 4.0