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Apr 14 at 15:30 history edited Perelman CC BY-SA 4.0
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Apr 6 at 16:44 comment added Perelman @TerryTao By the way, regarding your post on mathoverflow.net/questions/23478/…, if this case hasn't been proposed as an answer already, I think this might also be a nice example of a false belief in mathematics, that we can always apply the chain rule for weak derivatives. But this is by no means intended to cause offense. I really appreciate your answer.
Apr 6 at 16:41 comment added Perelman @TerryTao Thank you for the book recommendation. I've thought about the hint for a while, and I might still overlook something, but as far as I can see, $F$ is already $C^1$. Its derivative is $\frac{2}{p^\prime}|x|^{\frac{2}{p^\prime}-1}$ $(p^\prime<2)$. However, the derivative is unbounded, so we don't have access to the chain rule for weak derivatives as far as I know; $F^\prime$ needs to be in $L^\infty$ for that. Unfortunately, $F^\prime_\varepsilon$ also isn't bounded. But we could cut off the derivative and consider the limit case. But I wasnt succesfull at that yet.
Apr 1 at 14:39 comment added Terry Tao Actually, on closer inspection, the fractional chain rule is not needed as one is working here with a full derivative rather than a fractional one. One way to proceed is to replace $F(x)$ by the regularization $F_\varepsilon(x) = (\varepsilon^2+x^2)^{\frac{1}{p'}-\frac{1}{2}} x$ and then take weak limits as $\varepsilon \to 0$. By the way, for a modern introduction to paradifferential calculus (including the fractional chain rule), I recommend Taylor's "Tools for PDE".
Apr 1 at 14:00 history edited Daniele Tampieri CC BY-SA 4.0
Additions + minor math Jaxing
Apr 1 at 5:03 comment added Terry Tao I think the proof provided by Raviart is incomplete at this step, but Lemma 1.1 is easy to establish in any event: write $|v|^{p-2} v$ as $F( |v|^{\frac{p-2}{2}} v)$, where $F(x) := |x|^{\frac{2}{p'}-1}x$, and apply the fractional chain rule (which perhaps was not fully available in Raviart's time).
Mar 31 at 14:18 history edited Perelman CC BY-SA 4.0
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Mar 31 at 14:11 vote accept Perelman
Mar 30 at 20:17 history edited Perelman CC BY-SA 4.0
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Mar 30 at 18:27 answer added Ayman Moussa timeline score: 3
Mar 30 at 16:12 comment added Perelman @JingeonAn-Lacroix do you have an idea how to show for a smooth function approaching $u$, that its weak derivatives also converge in $L^1_{loc}$ at least
Mar 30 at 16:11 history undeleted Perelman
Mar 30 at 15:36 history deleted Perelman via Vote
Mar 30 at 15:33 comment added Perelman I cant quite follow, how does that imply that for $u$ being some function that its weak derivative exists?
Mar 30 at 15:04 comment added Jingeon An-Lacroix For example, you can mollify $u$ and get the wanted identity, then show the identity is preserved when mollification sent to identity? Of course we have to show some estimates along the way?
Mar 30 at 14:49 comment added Perelman Where do you know that $u$ has a weak derivative or $|u|^{(p-2)/2}$?
Mar 30 at 14:46 comment added Jingeon An-Lacroix What difficulty are you having? Just applying the product rule (with being careful with conditions) is not enough?
Mar 30 at 14:43 history edited Perelman CC BY-SA 4.0
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S Mar 30 at 13:16 review First questions
Mar 30 at 14:30
S Mar 30 at 13:16 history asked Perelman CC BY-SA 4.0