Attempt 3 (in response to Ben): every one of these maps $\hat{h}_{\alpha a}$ can be identified with a $G\times G'$-equivariant map $\Phi_{\alpha a}:U_{\alpha a}\times(G\times G')\to C^{\infty}(F,F')$ as follows: $$\Phi_{\alpha a}:\quad (p,g,g')\mapsto \left(f\mapsto g' \hat{h}_{\alpha a}\left(h(p),g^{-1}f\right)\right).$$ The action of $G\times G'$ on $C^{\infty}(F,F')$ is by composition $(g,g',\varphi)\mapsto g'\circ\varphi\circ g^{-1}$. The transformation rule becomes very simple: $$\boxed{\Phi_{\beta b}(p,g,g')=\Phi_{\alpha a}\left(p,t_{\beta\alpha}(p)g,t_{ba}'(h(p))g'\right).}$$ This clearly defines a global equivariant function on a principal $(G\times G')$-bundle but I want to omit that. I would like to set some restriction on these maps so that I could say that $h$ respects the $G$- and $G'$-structures in some sense. I can do it by analogy with the interpretation of a $G$-structure as a way of selecting an orbit inside the set of all isomorphisms: require all $\Phi_{\alpha a}$'s to take values in a single orbit of the action of $G\times G'$ on $C^\infty(F,F')$. This is a well-defined restriction because transition functions take values in $G\times G'$. It means that, up to a choice of local charts (compatible with the structures), the morphism "looks the same" in every fiber. Now, if $F$ and $F'$ have additional structure which selects in a natural way a subclass of maps $\mathrm{Hom}(F,F')\subset C^\infty(F,F')$ (and usually such that $G$ and $G'$ are the groups of isomorphismsautomorphisms preserving those structures), then we also require those orbits to be orbits of maps from $\mathrm{Hom}(F,F')$.