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Mar 27 at 16:26 history edited Michael Hardy CC BY-SA 4.0
\operatorname{Perf}, and also 0 belongs within MathJax
Mar 26 at 15:40 vote accept cellular
Mar 26 at 14:23 answer added Maxime Ramzi timeline score: 3
Mar 26 at 14:20 comment added Maxime Ramzi Actually, I realized the answer is no either way. I thought it would be yes if you didn't allow retracts but that's only if the thick closure of $C$ is the whole of $Perf(R)$.
Mar 26 at 12:50 comment added cellular @MaximeRamzi since you are rising the question, I'm open to all possibilities. What would the answer if we will (will not) allow retracts.
Mar 26 at 12:40 comment added Maxime Ramzi It depends what you mean by "generated". Do you allow retracts ?
Mar 26 at 12:14 history edited cellular CC BY-SA 4.0
added 27 characters in body
Mar 26 at 12:14 comment added cellular @pbelmans Thanks I forgot to mention that E is concentrated in degree 0.
Mar 26 at 12:12 comment added pbelmans The class of $E=R\oplus R[1]$ vanishes, but $E$ generates everything, so this cannot be true.
Mar 26 at 12:03 history asked cellular CC BY-SA 4.0