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Mar 23 at 18:10 answer added kindasorta timeline score: 1
Mar 23 at 15:19 comment added kindasorta In your view, $g(p)$ is the path which satisfies $g(p) = g(F_y)pg^{-1}(F_x)$. I guess the point which I find unclear is: if I replace my Galois element acting on $F_y$ by another element, would I still get a path? For example, is $h(F_y)pg^{-1}(F_x)$ a valid etale path for any $g,h\in G_k$?
Mar 23 at 14:31 comment added KristianJS It might be easier to see what it looks like from the fiber functor perspective. The torsor of etale paths = Isom(F_x, F_y) for the fiber functors F_x, F_y. An iso. is essentially given by maps between the fibers Y_x and Y_y for all covers Y. Given such a map you can act by Gal on both sides and get a new isom. If I didn't make a dumb mistake that's basically the Galois action. Then you can always translate back from fiber functor picture to check what this action corresponds to.
Mar 23 at 14:05 history edited LSpice CC BY-SA 4.0
'etale' -> 'étale'
Mar 23 at 13:52 history edited kindasorta CC BY-SA 4.0
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Mar 23 at 13:40 history asked kindasorta CC BY-SA 4.0