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Mar 20 at 18:53 history edited Will Sawin CC BY-SA 4.0
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Mar 20 at 18:38 history edited Will Sawin CC BY-SA 4.0
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Mar 20 at 18:35 comment added Will Sawin @StefanKohl Right, true. Sufficiently many minor adjustments should make that disappear, e.g. This one with $N^8-1$ might be OK. One might need to take $N^8 + N + 1$ or something like that, which is a much nicer polynomial for this sort of thing.
Mar 20 at 18:33 history edited Will Sawin CC BY-SA 4.0
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Mar 20 at 17:59 comment added Stefan Kohl Well — but doesn't the Pell equation in this always have the solution $(x,y) = (N^4,1)$, or did I misread something?
S Mar 20 at 16:52 history answered Will Sawin CC BY-SA 4.0
S Mar 20 at 16:52 history made wiki Post Made Community Wiki by Will Sawin