Timeline for Do separable $C^*$-algebras form a set?
Current License: CC BY-SA 2.5
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 20, 2010 at 20:06 | vote | accept | Kolya Ivankov | ||
| Nov 20, 2010 at 19:46 | comment | added | Andreas Thom | @Kolya: Ok, no problem. | |
| Nov 20, 2010 at 19:38 | comment | added | Kolya Ivankov | Once more, I apologize for not giving a reference and changing the question. Also, the way I tried to answer my question was still \emph{wrong}, because there still was written \emph{$C^*$-algebras} instead of \emph{isomorphism classes}. Thus, Your answer was the FULL answer anyway. In order to recover my fault, I promise to include Your name in the list of acknowledgments to my thesis. In fact, I was determined to do so anyway, because You and others have answered my questions before, and these answers were truly helpful, as well as this one. Again, I'm thankful and beg your pardon. | |
| Nov 20, 2010 at 16:30 | vote | accept | Kolya Ivankov | ||
| Nov 20, 2010 at 19:40 | |||||
| Nov 20, 2010 at 14:56 | comment | added | Joel David Hamkins | And meanwhile, each isomorphism class is a proper class, since we can find an isomorphic copy of any given $C^*$-algebra by replacing any element of it with any other object in the set-theoretic universe not already appearing in the algebra. | |
| Nov 20, 2010 at 13:35 | history | answered | Andreas Thom | CC BY-SA 2.5 |