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Timeline for Subgroup of p-adic units

Current License: CC BY-SA 4.0

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Mar 19 at 15:51 comment added Antonius But $\widehat{\mathbb{Z}^\times}$ is.
Mar 19 at 14:40 comment added Chris Wuthrich Don't worry, I think there was no danger that you are misunderstood. Similarly $\mathbb{Z}_p^{\times}$ is not the $p$-adic completion of $\{\pm1\}$.
Mar 19 at 14:23 history edited Antonius CC BY-SA 4.0
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Mar 19 at 14:22 comment added Antonius No, the times is correct, otherwise we have the profinite completion of the unit group of $\mathbb Z$, which is $\{\pm 1\}$. I have put brackets around the ring, to make it clear, what I mean.
Mar 18 at 17:07 history became hot network question
Mar 18 at 13:43 history edited gmvh CC BY-SA 4.0
Removed extra "is"
Mar 18 at 13:09 comment added LSpice TeX note: $\widehat{\mathbb Z}^\times$ \widehat{\mathbb Z}^\times puts the \times too high. To get it at the proper level, you can \smash the \widehat{\mathbb Z} to force TeX to forget its height: $\smash{\widehat{\mathbb Z}}^\times$ \smash{\widehat{\mathbb Z}}^\times. I have edited accordingly.
Mar 18 at 13:09 history edited LSpice CC BY-SA 4.0
`\smash`
Mar 18 at 11:22 vote accept Antonius
Mar 18 at 11:11 answer added GH from MO timeline score: 5
Mar 18 at 10:47 history edited YCor
edited tags
Mar 18 at 10:43 history edited Antonius CC BY-SA 4.0
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Mar 18 at 10:00 comment added Antonius Sorry, I meant dense in the unit group, not the ring. I am not sure, whether a similar argument applies for the unit group.
Mar 18 at 9:51 history edited Antonius CC BY-SA 4.0
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Mar 18 at 9:32 comment added YCor A subgroup is dense iff it is contained in $\ell\widehat{\mathbf{Z}}$ for no prime $\ell$. Given this, you should be able to answer your question.
Mar 18 at 9:06 history asked Antonius CC BY-SA 4.0