Timeline for Profinite topologies
Current License: CC BY-SA 2.5
4 events
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| Nov 20, 2010 at 6:01 | history | rollback | Alex B. |
Rollback to Revision 1
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| Nov 20, 2010 at 5:52 | comment | added | Alex B. | Clearly, if $P\subseteq N$, then the index of $P$ in $G$ is divisible by that of $N$ in $G$. So your equivalent condition is satisfied if and only if each finite quotient of $G$ is a $p$-group. | |
| Nov 20, 2010 at 5:45 | history | edited | Romeo |
edited tags
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| Nov 20, 2010 at 5:39 | history | asked | Alves | CC BY-SA 2.5 |