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Mar 23 at 17:09 comment added JoshuaZ It is a folklore conjecture that this will be about as difficult as factoring in general. The answer of Terry Tao in the earlier linked question above helps give part of the reason for why we think this.
Mar 23 at 12:11 history edited user2284570
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Mar 14 at 13:01 comment added Daniel Weber As far as I know there aren't any such results then, but I also don't know any proof of equivalence (and I don't expect that one exists)
Mar 14 at 12:55 comment added user2284570 @CommandMaster question is about random numbers not generating such numbers. I’m not interested in generating such numbers but finding such numbers in the result of a specific custom hash function.
Mar 14 at 6:40 comment added Daniel Weber There are some methods to create unfactored semiprimes with elliptic curves, but I don't know the details. See graysage.com/djr/isp.txt and eprint.iacr.org/2021/1610 . What do you need it for?
Mar 14 at 6:05 history edited user2284570 CC BY-SA 4.0
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Mar 14 at 2:15 history edited Todd Trimble CC BY-SA 4.0
composite --> divisor
Mar 12 at 22:43 comment added user2284570 @MaxAlekseyev but unlike mathoverflow.net/a/10062 knowing a large number is made of 2 prime divisors don t simplify factorization.
Mar 12 at 22:24 history edited user2284570 CC BY-SA 4.0
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Mar 12 at 22:22 history edited user2284570 CC BY-SA 4.0
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Mar 12 at 22:21 comment added Max Alekseyev See mathoverflow.net/q/3820
Mar 12 at 22:17 history edited user2284570 CC BY-SA 4.0
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S Mar 12 at 21:59 review First questions
Mar 12 at 23:10
S Mar 12 at 21:59 history asked user2284570 CC BY-SA 4.0