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Mar 5 at 22:12 comment added Pedram I realized that adding 0 to 𝐷 will make 𝑋 smaller than what I described in my comment earlier. Is that why you added the 0?
Mar 5 at 21:25 comment added Pedram If D doesn't have a 0, then stage 3 would create a companion element for every element of D since in the absence of 0, no element is an atom, either. Also, in the absence of 0, we can modify the requirement "$x_d$ is strictly above 0" to "$x_d$ is not the minimum element of the final set $X$", right? Or would this violate property 2?
Mar 5 at 20:31 comment added Pedram I have a couple of clarifying questions (I'm new to some terminologies): 1) In stage 2, is $(D, \succeq)$ the smallest meet-subsemilattice of $(C, \succeq)$ that contains the elements of $\{h(x)|x\in P\}$? 2) Why do you add a 0 to D in stage 2? Is it to guarantee that for every $x, y \in X$, $x\wedge y$ exists in $X$? If so, wouldn't property 2 of my question (the original one, not the strengthening of it) be still satisfied even without adding a 0? Thanks!
Mar 4 at 21:40 history edited Alec Rhea CC BY-SA 4.0
got the succ
Mar 4 at 16:23 vote accept Pedram
Mar 4 at 14:09 history edited Keith Kearnes CC BY-SA 4.0
deleted 13 characters in body
Mar 4 at 3:52 history answered Keith Kearnes CC BY-SA 4.0