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Let $K$ be an algebraically closed field. Denote by $\mathcal F_d$ the category of extensions $K\to F$ of transcendent degree $d$.(Objects are pairs $F,j$ consisting of a field extensions $K\to F$$F$ and the embedding $j\colon K\to F$, such that transcendent degree is equal to $d$, morphisms between $(F_1,j_1)$ and $(F_2,j_2)$ are finite extensions $F_1\to F_2$, respecting$\psi\colon F_1\to F_2$ such that $K$$\psi\circ j_1=j_2$). Consider the category of (covariant) functors $Fun(\mathcal F_d, \mathcal{Vect})$ from this category to the category of vector spaces over $\mathbb Q$. What is known about its cohomological dimension?

Especially we have a functor which associate to a field extension $K\to F$ the multiplicative group $(F^\times)\otimes \mathbb Q$. Is it true that all higher cohomology of this functor vanishes?

Let $K$ be an algebraically closed field. Denote by $\mathcal F_d$ the category of extensions $K\to F$ of transcendent degree $d$.(Objects are field extensions $K\to F$, morphisms are finite extensions $F_1\to F_2$, respecting $K$). Consider the category of functors $Fun(\mathcal F_d, \mathcal{Vect})$ from this category to the category of vector spaces over $\mathbb Q$. What is known about its cohomological dimension?

Especially we have a functor which associate to a field extension $K\to F$ the multiplicative group $(F^\times)\otimes \mathbb Q$. Is it true that all higher cohomology of this functor vanishes?

Let $K$ be an algebraically closed field. Denote by $\mathcal F_d$ the category of extensions $K\to F$ of transcendent degree $d$.(Objects are pairs $F,j$ consisting of a field $F$ and the embedding $j\colon K\to F$, such that transcendent degree is equal to $d$, morphisms between $(F_1,j_1)$ and $(F_2,j_2)$ are finite extensions $\psi\colon F_1\to F_2$ such that $\psi\circ j_1=j_2$). Consider the category of (covariant) functors $Fun(\mathcal F_d, \mathcal{Vect})$ from this category to the category of vector spaces over $\mathbb Q$. What is known about its cohomological dimension?

Especially we have a functor which associate to a field extension $K\to F$ the multiplicative group $(F^\times)\otimes \mathbb Q$. Is it true that all higher cohomology of this functor vanishes?

added 57 characters in body
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Let $K$ be an algebraically closed field. Denote by $\mathcal F_d$ the category of extensions $K\to F$ of transcendent degree $d$.(J,jectsObjects are field extensions $K\to F$, morphisms are finite extensions $F_1\to F_2$, respecting $K$). Consider the category of functors $Fun(\mathcal F_d, \mathcal{Vect})$ from this category to the category of vector spaces over $\mathbb Q$. What is known about its cohomological dimension?

Especially we have a functor which associate to a field extension $K\to F$ the multiplicative group $F^\times$$(F^\times)\otimes \mathbb Q$. Is it true that all higher cohomology of this functor vanishes?

Let $K$ be an algebraically closed field. Denote by $\mathcal F_d$ the category of extensions $K\to F$ of transcendent degree $d$.(J,jects are field extensions, morphisms are finite extensions). Consider the category of functors $Fun(\mathcal F_d, \mathcal{Vect})$ from this category to the category of vector spaces over $\mathbb Q$. What is known about its cohomological dimension?

Especially we have a functor which associate to a field extension $K\to F$ the multiplicative group $F^\times$. Is it true that all higher cohomology of this functor vanishes?

Let $K$ be an algebraically closed field. Denote by $\mathcal F_d$ the category of extensions $K\to F$ of transcendent degree $d$.(Objects are field extensions $K\to F$, morphisms are finite extensions $F_1\to F_2$, respecting $K$). Consider the category of functors $Fun(\mathcal F_d, \mathcal{Vect})$ from this category to the category of vector spaces over $\mathbb Q$. What is known about its cohomological dimension?

Especially we have a functor which associate to a field extension $K\to F$ the multiplicative group $(F^\times)\otimes \mathbb Q$. Is it true that all higher cohomology of this functor vanishes?

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Cohomological dimension of functors from fields to vector spaces

Let $K$ be an algebraically closed field. Denote by $\mathcal F_d$ the category of extensions $K\to F$ of transcendent degree $d$.(J,jects are field extensions, morphisms are finite extensions). Consider the category of functors $Fun(\mathcal F_d, \mathcal{Vect})$ from this category to the category of vector spaces over $\mathbb Q$. What is known about its cohomological dimension?

Especially we have a functor which associate to a field extension $K\to F$ the multiplicative group $F^\times$. Is it true that all higher cohomology of this functor vanishes?