Timeline for Norm of a matrix function of a vector $x$
Current License: CC BY-SA 4.0
12 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Feb 22 at 21:13 | comment | added | Iosif Pinelis | @Shoeb : Does this answer fully (even if negatively) answer your question? If so, then these guidelines may be relevant. | |
Feb 22 at 16:30 | comment | added | Shoeb | Yes, got it. Thank you for the response. | |
Feb 21 at 21:01 | comment | added | Iosif Pinelis | @Shoeb : Again, your question has now been answered (negatively). Have you seen and read this answer? | |
Feb 21 at 20:47 | comment | added | Shoeb | Yes indeed [Iosif Pinelis] and [Denis Serre], i switched the order. Yes, I am referring to operator norm. Is it correct that $\|A(x)\| \le 1 \forall x$? | |
Feb 21 at 19:30 | comment | added | Iosif Pinelis | Ah, I see. I think this is what the OP denoted simply by $\|\cdot\|_2$, with the $\cdot$ standing for a matrix. This norm was considered in the last paragraph of my answer, and apparently concerning this case the OP said "I see that [...]". So, it does not appear to me that the question was about $\|\cdot\|_{2,2}$. | |
Feb 21 at 19:22 | comment | added | Christian Remling | $\|A\|_{2,2}=\max_{\|x\|_2=1}\|Ax\|_2$ | |
Feb 21 at 19:21 | comment | added | Iosif Pinelis | @ChristianRemling : What do you mean by the $\|\cdot\|_{2,2}$ norm? | |
Feb 21 at 15:52 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
added 1 character in body
|
Feb 21 at 15:40 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
added 198 characters in body
|
Feb 21 at 15:34 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
added 198 characters in body
|
Feb 21 at 15:23 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
deleted 112 characters in body
|
Feb 21 at 15:08 | history | answered | Iosif Pinelis | CC BY-SA 4.0 |