Timeline for Is a fibre bundle over a vector bundle trivializable on each fibre?
Current License: CC BY-SA 2.5
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 1, 2010 at 21:39 | vote | accept | mathbekunkus | ||
| Nov 18, 2010 at 5:34 | answer | added | Sean Tilson | timeline score: 2 | |
| Nov 18, 2010 at 0:16 | comment | added | David Roberts♦ | Are you supposing $\Pi$ is a principal bundle? If not, then it can't be homogeneous, at least by how I understand homogeneous bundles (=quotients of Lie groups by subgroups). And As Somnath says, locally trivial bundles over a fin. dim. vector space (with the usual topology) are globally trivial. | |
| Nov 18, 2010 at 0:07 | comment | added | Somnath Basu | Since $E_p$ is a vector space, it is contractible. This should be enough to guarantee that any fibre bundle over $E_p$ is trivializable. | |
| Nov 18, 2010 at 0:03 | history | asked | mathbekunkus | CC BY-SA 2.5 |