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Feb 3, 2011 at 5:53 comment added Steve Lack only just saw this - belated thanks and g'day
Nov 19, 2010 at 6:56 vote accept roger123
Nov 19, 2010 at 1:28 comment added Steve Lack Yes, that's it.
Nov 18, 2010 at 14:10 comment added roger123 Thank you for the answer, Steve. May I formulate it in this way: The commuting property is fulfilled iff for every functor $F:C\times D\to A$ it does not matter if I first apply the colimit functor to the first "factor" and get a functor $F':D\to A$ to which I apply the limit functor or if I do it the other way round?
Nov 18, 2010 at 10:40 comment added Steve Lack Good point about the homotopy case. One example (in the non-homotopy case) where pushouts and pullbacks do commute is in a groupoid. But pullbacks and pushouts in groupoids are not very interesting.
Nov 18, 2010 at 3:06 comment added Tom Goodwillie If we pass from category theory to homotopy theory, we can consider whether D-shaped homotopy limits commute (up to natural weak equivalence) with C-shaped homotopy colimits. This is not so rare. If the category is pointed then it is the same as what is commonly called stable. Typical examples are spectra, or (unbounded) chain complexes of R-modules. It's also the same as saying that a square diagram is a homotopy pushout iff it is a homotopy pullback. Also the same as: finite homotopy colimits commute with all homotopy limits (or vice versa).
Nov 17, 2010 at 23:15 comment added David Roberts Welcome, Steve!
Nov 17, 2010 at 23:04 history answered Steve Lack CC BY-SA 2.5