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Feb 16 at 17:02 vote accept tomasz
Feb 16 at 16:31 answer added tomasz timeline score: 4
Feb 14 at 18:17 review Close votes
Feb 23 at 3:03
Feb 14 at 17:52 comment added tomasz @YCor: Wow, that's embarrasing. Can you post this as an answer so that I can accept it? Or I can just post it as CW if you prefer.
Feb 14 at 16:36 history edited tomasz CC BY-SA 4.0
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Feb 14 at 16:36 comment added YCor Yes (in the category of all groups, or in the category of all fg groups), take $G$ free: then $H$ embeds into $G$, so $H$ is free (Nielsen-Schreier theorem).
Feb 14 at 16:35 history asked tomasz CC BY-SA 4.0