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Mar 6 at 21:59 vote accept Yanlong Hao
Feb 14 at 15:54 answer added Peter Mueller timeline score: 3
Feb 14 at 0:02 comment added Yanlong Hao @PeterMueller Thanks for asking. The $L_\infty$ bounds here is $\infty$. Even considering the function g(x)=xf(x), the possible $L_\infty$ bounds after shift down is possible close to 2.5. Hence it is related but does not answer the question..
Feb 13 at 22:57 comment added Peter Mueller @Yanlong Hao Doesn't the technique in David Speyer's answer of your very similar previous question mathoverflow.net/questions/458834 apply here?
Feb 13 at 17:32 comment added Daniel Weber Because $f(1), f(2), f(3), f(4)$ must actually be extrema, we can get the value $\mod (x-1)^2 (x-2)^2 (x-3)^2 (x-4)^2$
Feb 13 at 17:25 comment added Daniel Weber We have $f(1), f(2), f(3), f(4) \in \{0, 1\}$, so there are at most 16 possibilities to $f(x) \mod (x-1)(x-2)(x-3)(x-4)$. This modulus must also have integer coefficients (because $(x-1)(x-2)(x-3)(x-4)$ is monic), and checking all the possibilities, it must be either $0$ or $1$.
Feb 13 at 14:02 history asked Yanlong Hao CC BY-SA 4.0