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Feb 13 at 7:27 comment added Salvo Tringali Yes, I agree. I just wanted to emphasize that the result in the OP is not exactly the same as Corollary 4 in Sasaki and Tamura's paper. It is rather that the former is a straightforward corollary of the latter.
Feb 13 at 4:15 comment added Benjamin Steinberg @SalvoTringali, yes. This is easy to see though since any two elements have a common multiple and so if one element goes to 0 they all do.
Feb 13 at 3:56 comment added Salvo Tringali So, to recover the result in the OP from Sasaki and Tamura's corollary, I think one should first argue (as trivial as it may be) that a monoid hom $f \colon H \to K$ between Puiseux monoids restricts to a sgrp hom between the "positive cones" of $H$ and $K$, unless $f$ is identically zero.
Feb 13 at 3:47 comment added Salvo Tringali I think that, by the term "positive rational semigroup", Sasaki and Tamura mean a (non-empty) subsemigroup of the positive rational numbers under addition. Corollary 4 in their paper says that any homomorphism between positive rational semigroups is in fact an isomorphism (of the form $x \mapsto rx$, where $r$ is a positive rational number). This is not the case with Puiseux monoids, but only because it is missing the zero homomorphism.
Feb 13 at 3:41 comment added Benjamin Steinberg I am confused. I think what they mean by positive rational semigroup is exactly puiseux monoids (except without the identity) and Cor 4 says every homomorphism between them is given by multiplication by a rational
Feb 13 at 3:30 vote accept Salvo Tringali
Feb 13 at 3:29 comment added Salvo Tringali Thanks! Corollary 4 in Sasaki and Tamura's paper does indeed imply the result in the OP, after noticing that a monoid homomorphism between Puiseux monoids must either be identically zero or map positive rationals to positive rationals (and hence restrict, in the terminology of Sasaki and Tamura, to a semigroup homomorphism of positive rational semigroups). Before asking here, I had the term "rational semigroup" in mind but couldn't remember why...
Feb 13 at 2:25 history answered Benjamin Steinberg CC BY-SA 4.0