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Feb 13 at 0:47 review Suggested edits
Feb 13 at 9:13
Feb 12 at 14:50 history edited Muniain
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Feb 12 at 14:49 history edited gmvh
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Feb 12 at 14:47 comment added Muniain One can show, by Fourier transform that $$\int_{\mathbb R^{d}}\left|(-\Delta)^{\frac{s}{2}} u\right|^{2} \geq \int_{\mathbb R^{d}}\left|(-\Delta)^{\frac{s}{2}} (u*g_{\mu})\right|^{2}.$$ The inequality that I asked is an improvement but it might not be true. Then I hope there is an estimate between the two terms with an error depending on $\mu$.
Feb 12 at 14:45 history edited Muniain CC BY-SA 4.0
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Feb 12 at 14:41 comment added Christian Remling Can I ask how you know that this is true? (Also, $\mathbb R^4$ in the second integral seems a typo.)
S Feb 12 at 14:28 review First questions
Feb 12 at 14:49
S Feb 12 at 14:28 history asked Muniain CC BY-SA 4.0