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S Feb 9 at 19:48 history suggested Paul Tupper CC BY-SA 4.0
changed "those these" to "but these"
Feb 9 at 17:14 review Suggested edits
S Feb 9 at 19:48
Feb 8 at 19:12 comment added YCor Just a comment on the last example ($(X,\delta)$ any infinite compact metric space with $d(x,y)=1/\delta(x,y)$ for $x\neq y$): every uncountable metric space has an finite (and even uncountable) bounded subspace. In this example, every infinite subset has an accumulation point, which means has pair of points for which the function $d$ tends to infinity, so cannot be bounded for any distance $\ge d$.
Feb 8 at 18:45 history edited David Bryant CC BY-SA 4.0
Fixed notation for the reals.
Feb 8 at 17:44 comment added Peter LeFanu Lumsdaine @YCor: Agreed, though it’s not absolutely nonexistent — I remember seeing it in some old-ish books (~60s or earlier), I think possibly in set theory?
Feb 8 at 17:38 comment added YCor Your notation $\Re$ is very unusual (it sometimes means real part, but not the set of reals). You probably mean $\mathbf{R}$ or $\mathbb{R}$.
Feb 8 at 17:33 history edited David Bryant CC BY-SA 4.0
Added additional information
Feb 8 at 16:18 comment added YCor If $X$ is countable this is easy by induction. Namely $X=\{x_i:i\ge 0\}$, $x_i$ distinct, and define $\rho(x_i,x_j)=u_j$ for $i<j$ with $u_j$ increasing, and large enough (namely $\ge \max_{i:i<j} d(x_i,x_j)$).
Feb 8 at 3:47 history asked David Bryant CC BY-SA 4.0