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Feb 8 at 5:41 comment added Ryan Budney @AndreyRyabichev: true, but it's called a spectrum in physics. So it's natural to do it in math as well. Mathematics does not have any special rights when it comes to the usage of the word "spectrum". I mean, think of how much mathematicians appropriate the word "quantum".
Feb 7 at 12:51 comment added D. Thomine There are also notions of Markov and Lagrange spectra, which are related to height (instead of length) of geodesics in the modular surface. However, I am not sure that the vocabulary of spectrum for these predates the length spectrum.
Feb 7 at 8:51 comment added Timothy Budd I am far from an expert here, but taking the question literally, you could have a look at Bismut's work on the hypoelliptic Laplacian, which, loosely speaking, deals with a family of operators that interpolates between the (Hodge) Laplacian and the generator of geodesic flow. In this way it provides a link between the Laplace spectrum and the length spectrum (in particular, chapter 8 deals with proving the Selberg trace formula in this way).
Feb 7 at 8:15 comment added Andrey Ryabichev @RyanBudney You are simply talking about a subset of the line. This subset can just as well be called a “length support” or a “length generator”, using other comparisons
Feb 7 at 4:53 comment added Ryan Budney Think of the spectrum of a hydrogen atom. Basically, it's a bunch of points on the real line, if you think of the real line as being frequencies of light. The length spectrum of a surface is again essentially just a bunch of points on the real line. So the comparison is pretty direct.
Feb 7 at 1:54 history edited RobPratt
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Feb 7 at 1:08 history became hot network question
Feb 6 at 20:29 comment added Terry Tao Another possible connection is that there is an analogy between primitive geodesics and primes (see e.g., en.wikipedia.org/wiki/Prime_geodesic ), and prime numbers are basically the spectrum of the integers (in the algebraic sense en.wikipedia.org/wiki/Spectrum_of_a_ring ).
Feb 6 at 20:25 comment added Terry Tao One simple calculation that might be suggestive: in a torus ${\bf R}^d/\Lambda$ with the Euclidean metric, the length spectrum is the set of squares of magnitudes of (irreducible) elements of the lattice $\Lambda$, while the spectrum of the Laplacian is the set of squares of magnitudes of elements of the dual lattice $\Lambda^*$. (Admittedly, this is not a hyperbolic manifold, though.)
Feb 6 at 19:41 answer added Sam Nead timeline score: 12
Feb 6 at 18:37 comment added Sam Hopkins I have no idea about this particular case, but the English word "spectrum" is a more general term than something which just applies to operators (e.g., think of the light spectrum in physics, or even within math, think of spectra in algebraic topology).
Feb 6 at 17:06 history asked Andrey Ryabichev CC BY-SA 4.0