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Feb 6 at 15:29 comment added kindasorta Does your argument also imply that every dense morphism of affine algebraic group schemes is faithfully flat?
Feb 5 at 21:53 comment added kindasorta I believe $Comodf(D)$ should be $Comod(D)$. Many thanks, this totally clarifies everything. Your answer suggest that there is a non-canonical filtration of the $k$-coalgebra of a neutral Tannakian group over $k$. I wonder if this can be used to compute Tannakian fundamental groups.
Feb 5 at 21:28 vote accept kindasorta
Feb 5 at 18:52 history answered anon CC BY-SA 4.0