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Jan 23, 2011 at 10:02 vote accept Hanno
Nov 17, 2010 at 22:24 comment added Georges Elencwajg Ah, I was really off base with my suggestion! Thanks for the bibliography.
Nov 17, 2010 at 22:04 comment added Neil Strickland @Georges: no, BP stands for Brown-Peterson here. See for example this book: goo.gl/snmbm or Wikipedia: en.wikipedia.org/wiki/Brown%E2%80%93Peterson_cohomology
Nov 17, 2010 at 21:48 comment added Georges Elencwajg Thank you for the example, Neil. Unfortunately, I don't know what stable homotopy theory is. But the ring you mention reminds me of the cohomology of infinite projective space . Does the $B$ in $BP_\ast$ stand for "classifying space" ?
Nov 17, 2010 at 15:26 comment added Neil Strickland @Georges: you are correct. (In stable homotopy theory we care about the case $R_*=BP_*=\mathbb{Z}_{(p)}[v_1,v_2,\dotsc]$ with $|v_i|=2(p^i-1)$, and of course that one is not Noetherian.)
Nov 17, 2010 at 14:52 comment added Georges Elencwajg Dear Neil, the OP's hypothesis that the graded ring be Noetherian is not necessary, is it?
Nov 17, 2010 at 13:07 history answered Neil Strickland CC BY-SA 2.5