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Feb 9 at 13:33 vote accept gmvh
Feb 3 at 18:21 comment added Aleksei Kulikov @gmvh since all the ones I constructed are multiplicative, the continuous ones are only of the form $c sign(x)|x|^s$ which you already know of.
Feb 3 at 17:05 comment added gmvh @AlekseiKulikov interesting! I wonder how many of these are continuous.
Feb 3 at 3:40 answer added Aleksei Kulikov timeline score: 1
Feb 3 at 3:14 comment added Aleksei Kulikov It seems to me I can construct $2^{\mathfrak{c}}$ such functions (which is obviously the biggest it can be) for $S =\mathbb{R}$ and even with $\beta_\lambda = 0$ always by taking logarithms and writing the abelian group $\mathbb{R}$ as a direct sum of $\mathfrak{c}$-many $\mathbb{R}$'s.
Feb 2 at 11:08 comment added gmvh @Nandor Well, non-empty is an obvious requirement to make this meaningful. In fact, I would like $S$ to contain an interval containing $1$, which I added. But if there are cases for another non-empty $S$, I'd be interested in those, as well.
Feb 2 at 11:06 history edited gmvh CC BY-SA 4.0
Reply to comment by Nandor
Feb 2 at 9:50 comment added Antonius Can you be more specific as to what you want $S$ to look like? The empty set would always do...
Feb 2 at 9:17 history edited gmvh CC BY-SA 4.0
Minor correction
Feb 2 at 8:15 history asked gmvh CC BY-SA 4.0