Timeline for Is the decomposition of an algebra into irreducible components essentially unique?
Current License: CC BY-SA 2.5
7 events
| when toggle format | what | by | license | comment | |
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| May 4, 2014 at 18:14 | comment | added | Goldstern | Bjarni Jónsson's example is very nice. But it seems to me that the group operation is not necessary; the unary function suffices. | |
| Nov 19, 2010 at 2:01 | comment | added | Gerhard Paseman | Looks like I might lose the wager. ALV in chapter 5.1 has a generalized version of the commutative semigroup exercise above, credited to R. McKenzie. (Not to be confused with Robert MacKenzie or John McKinsey.) Gerhard "Betting Windows Are Now Closed" Paseman, 2010.11.18 | |
| Nov 18, 2010 at 21:36 | comment | added | Gerhard Paseman | I suspect the R is not an R. Even so, there is at least one McKinsey who did some structure theory. I will wager a small amount of money that it is not Ralph McKenzie. Gerhard "Ask Me About System Design" Paseman, 2010.11.18 | |
| Nov 17, 2010 at 10:31 | vote | accept | Andrej Bauer | ||
| Nov 17, 2010 at 4:18 | comment | added | Gerald Edgar | So, I wonder if "R. McKinsey" is "Ralph McKenzie"... | |
| Nov 17, 2010 at 1:09 | history | edited | Gerald Edgar | CC BY-SA 2.5 |
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| Nov 17, 2010 at 1:00 | history | answered | Gerald Edgar | CC BY-SA 2.5 |