Timeline for Solvability of $A X B=C$ with $X=X^\mathrm{T}$
Current License: CC BY-SA 4.0
8 events
when toggle format | what | by | license | comment | |
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Feb 7 at 12:33 | vote | accept | Juan | ||
Jan 31 at 22:37 | history | edited | loup blanc | CC BY-SA 4.0 |
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Jan 31 at 14:36 | comment | added | Juan | That's great progress for sure! I still fail to see how the "only if" statement is justified though, cause if $dim(E_k \cap F_m)\geq 1$, how can you be sure that there is no symmetric solution that doesn't require such symetric extension? | |
Jan 30 at 22:45 | history | edited | loup blanc | CC BY-SA 4.0 |
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Jan 29 at 11:31 | comment | added | Juan | Correction on my previous comment: "It doesn't make much sense..." | |
Jan 29 at 10:32 | comment | added | Juan | I am not that familiar with the concept of transversability, but is it possible that $R$ and $S$ are not generically transverse due to the structure of the problem? If so, do you think this could be actually proven? It does make much sense that if the dimension of $dim(R\cap S)$ is greater than 1 there is no solution does it. | |
Jan 28 at 14:10 | history | edited | loup blanc | CC BY-SA 4.0 |
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Jan 28 at 0:26 | history | answered | loup blanc | CC BY-SA 4.0 |