Timeline for A strange condition of convexity?
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
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| Jan 26 at 0:26 | comment | added | Christian Remling | In fact, it would have been slightly easier to not go back to $f$ at all: $g(x)\to 0$, so $g'\to -1$, which would make $g$ negative eventually, but clearly $g\ge 0$ under our assumptions on $f$. | |
| Jan 25 at 21:30 | history | edited | Christian Remling | CC BY-SA 4.0 |
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| Jan 25 at 18:00 | comment | added | Christian Remling | @IosifPinelis: I was indeed a bit sloppy at the end, but everything is fine as written anyway: $g=f'/f\le ae^{-x}$, so $f'$ does go to zero. Even if it didn't, we still have $f'\in L^1$ from $f\to L$, so $f''+f\in L^1$, and then integrating we obtain $f'(x)=-Lx + o(x)$, which is good enough. | |
| Jan 25 at 17:28 | vote | accept | Dattier | ||
| Jan 25 at 17:05 | history | answered | Christian Remling | CC BY-SA 4.0 |