Timeline for Can this kind of Mereology be synonymous with Set Theory?
Current License: CC BY-SA 4.0
19 events
| when toggle format | what | by | license | comment | |
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| Jan 30 at 20:34 | history | edited | Zuhair Al-Johar | CC BY-SA 4.0 |
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| Jan 30 at 4:28 | history | edited | Zuhair Al-Johar | CC BY-SA 4.0 |
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| Jan 29 at 18:29 | history | edited | Zuhair Al-Johar | CC BY-SA 4.0 |
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| Jan 29 at 18:22 | history | edited | Zuhair Al-Johar | CC BY-SA 4.0 |
added 44 characters in body
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| Jan 29 at 18:15 | history | edited | Zuhair Al-Johar | CC BY-SA 4.0 |
added 44 characters in body
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| Jan 28 at 17:33 | history | edited | Zuhair Al-Johar | CC BY-SA 4.0 |
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| Jan 28 at 10:06 | history | edited | Zuhair Al-Johar | CC BY-SA 4.0 |
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| Jan 28 at 7:19 | vote | accept | Zuhair Al-Johar | ||
| Jan 28 at 3:53 | history | edited | Zuhair Al-Johar | CC BY-SA 4.0 |
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| Jan 27 at 21:48 | answer | added | paste bee | timeline score: 3 | |
| Jan 26 at 12:12 | history | edited | Zuhair Al-Johar | CC BY-SA 4.0 |
added 358 characters in body
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| Jan 26 at 12:01 | comment | added | Zuhair Al-Johar | @pastebee, Thanks! I've corrected it. | |
| Jan 26 at 11:24 | history | edited | Zuhair Al-Johar | CC BY-SA 4.0 |
deleted 1 character in body
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| Jan 26 at 10:00 | comment | added | paste bee | Supplementation is the wrong way around. If $x = \mathbb{N}$ and $y = {0}$, then no subset of $y$ is disjoint from $x$, but there are subsets of $x$ that are disjoint from $y$. | |
| Jan 26 at 8:29 | history | edited | Zuhair Al-Johar | CC BY-SA 4.0 |
deleted 25 characters in body
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| Jan 25 at 22:40 | history | edited | Michael Hardy | CC BY-SA 4.0 |
better MathJax usage
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| Jan 25 at 16:16 | history | edited | Zuhair Al-Johar | CC BY-SA 4.0 |
edited body
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| Jan 25 at 14:33 | history | edited | Zuhair Al-Johar | CC BY-SA 4.0 |
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| Jan 25 at 12:00 | history | asked | Zuhair Al-Johar | CC BY-SA 4.0 |