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when toggle format what by license comment
Jan 25 at 5:46 history edited Daniele Tampieri CC BY-SA 4.0
Minor Math Jaxing
Jan 24 at 20:52 comment added Giorgio Metafune Yes and this follows from the scalar case: $\|D^2 u\|_2 =\|\Delta u\|_2$ where $(D^2 u)$ is the Hessian matrix of $u$. Having this, $\|D^2_{ik}u_i\|_2^2 \leq \|\Delta u_i\|_2^2$ for $i=1,2,3$ which gives the inequality componentwise.
S Jan 24 at 20:17 review First questions
Jan 25 at 5:46
S Jan 24 at 20:17 history asked Alberto Leandro CC BY-SA 4.0