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Jan 23 at 13:48 answer added user515519 timeline score: 2
Jan 23 at 8:29 comment added YCor @RyanBudney For an exotic circle $\mathbf{R}_{>0}/\langle t\rangle$ holonomy yields locally multiplication by $t$, so you don't consistently get a Riemannian metric in this way.
Jan 23 at 8:16 comment added Sergiy Maksymenko Thank you very much, Ryan. Your arguments probably extend to compact affine manifolds, so they might not have affine atlases with surjective charts, since otherwise they would have infinite volume in some metric constructed by that atlas
Jan 23 at 8:00 answer added YCor timeline score: 6
Jan 23 at 7:42 comment added Ryan Budney One way to approach this (perhaps not the most efficient) would be to use the affine charts to put a Riemann metric on the manifold, by pulling back the standard metric on the co-domains. If your charts had co-domain $\mathbb R$ your circle would have infinite length, contradicting compactness.
Jan 23 at 7:16 history edited Sergiy Maksymenko CC BY-SA 4.0
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Jan 23 at 6:57 history asked Sergiy Maksymenko CC BY-SA 4.0