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Jan 20 at 6:54 comment added Jeremy Rickard @Mare Yes, it has dominant dimension zero.
Jan 20 at 3:00 comment added Mare Your algebra has dominant dimension zero, or? For positive dominant dimension the formula should be correct I think. Maybe the definition of the stable module should be modified for dominant dimension zero. Maybe one should define instead $\underline{A} :=A/AeA$, where $eA$ is such that $add(eA)$ is a projective cover of $D(A)$. I will do some tests.
Jan 18 at 13:30 comment added Mare Thank you. I tested the question only for finite projective dimension modules (as the computer can only calculate finitely many things). But I am still a bit surprised that it is not true in general.
Jan 18 at 9:18 history answered Jeremy Rickard CC BY-SA 4.0