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Jan 19 at 2:13 vote accept onefishtwofish
Jan 18 at 21:50 comment added Oli Gregory That $F$ is horizontal is just functoriality. For the Gauss-Manin connection you can look at Katz-Oda, On the differentiation of de Rham cohomology classes with respect to parameters., J. Math. Kyoto Univ. 8 (1968), 199–213. To see that the connection coming from the crystal is the same as the Gauss-Manin connection, see Chapitre V.3.6 in the Berthelot reference in my answer.
Jan 18 at 0:50 comment added onefishtwofish Thanks! This is helpful. Where can I find the statement that 𝐹 is horizontal for ∇? Would you mind saying a few words about that? Also in a related point, how are we defining the Gauss-Manin connection on crystalline cohomology? (I'm sorry if that's a very ignorant question.)
Jan 17 at 21:57 history answered Oli Gregory CC BY-SA 4.0