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Jan 17 at 18:52 comment added Lawrence D'Anna Thank you! That makes perfect sense.
Jan 17 at 18:02 comment added Igor Khavkine The amount of geometric formalism obscures somewhat might be the core of your confusion. Writing things out in canonical coordinates on $T^*Q$ reveals that half of the $\Omega(X,-) = dH$ system is equivalent to $JX=\Delta$ by a crucial property of the Legendre transform, namely its involutivity ($\dot{q} = \frac{\partial H}{\partial p}\left(p=\frac{\partial L}{\partial \dot{q}}(\dot{q})\right)$).
Jan 16 at 15:39 history asked Lawrence D'Anna CC BY-SA 4.0