Timeline for Minimum number of transpositions to make two multiset permutations equal
Current License: CC BY-SA 4.0
8 events
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Jan 30 at 9:16 | history | edited | caduk | CC BY-SA 4.0 |
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Jan 16 at 7:11 | vote | accept | Fabius Wiesner | ||
Jan 15 at 21:39 | comment | added | Luc Guyot | ... cannot be the product of less than $m(n - 1)$ transpositions. | |
Jan 15 at 21:36 | comment | added | Luc Guyot | Many thanks for your input. I think I get the second part: there is a surjective forgetful map from $\text{Sym}(mn)$ (the labeled permutations) onto the permutations of the OP's multiset (those are label-less permutations), that is, the natural map $\text{Sym}(mn) \rightarrow \text{Sym}(mn) / \text{Sym}(m)^n$. Then you exhibit a special element $\sigma$ such that $\sigma \theta$ has exactly $m$ cycles for every $\theta \in \text{Sym}(m)^n$. This means that the reflection length of $\sigma \theta$ is $m(n - 1)$ for every $\theta$. Hence $\sigma$, as a permutation of the multiset ... | |
Jan 15 at 13:52 | comment | added | caduk | @FabiusWiesner done, there was a slight mistake, we can have less than $m$ cycles (but not more) | |
Jan 15 at 13:51 | history | edited | caduk | CC BY-SA 4.0 |
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Jan 15 at 10:45 | comment | added | Fabius Wiesner | Could you give an example for the last statement? | |
Jan 15 at 9:00 | history | answered | caduk | CC BY-SA 4.0 |