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Jan 30 at 9:16 history edited caduk CC BY-SA 4.0
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Jan 16 at 7:11 vote accept Fabius Wiesner
Jan 15 at 21:39 comment added Luc Guyot ... cannot be the product of less than $m(n - 1)$ transpositions.
Jan 15 at 21:36 comment added Luc Guyot Many thanks for your input. I think I get the second part: there is a surjective forgetful map from $\text{Sym}(mn)$ (the labeled permutations) onto the permutations of the OP's multiset (those are label-less permutations), that is, the natural map $\text{Sym}(mn) \rightarrow \text{Sym}(mn) / \text{Sym}(m)^n$. Then you exhibit a special element $\sigma$ such that $\sigma \theta$ has exactly $m$ cycles for every $\theta \in \text{Sym}(m)^n$. This means that the reflection length of $\sigma \theta$ is $m(n - 1)$ for every $\theta$. Hence $\sigma$, as a permutation of the multiset ...
Jan 15 at 13:52 comment added caduk @FabiusWiesner done, there was a slight mistake, we can have less than $m$ cycles (but not more)
Jan 15 at 13:51 history edited caduk CC BY-SA 4.0
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Jan 15 at 10:45 comment added Fabius Wiesner Could you give an example for the last statement?
Jan 15 at 9:00 history answered caduk CC BY-SA 4.0