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Jan 10 at 14:35 comment added Sasha If you look at the proof of the Borel--Bott--Weil Theorem (e.g., in the paper of Demazure) you will see that $H^m$ iis identified, eventually, with $H^0$ of a different bundle, and typically $s$ induces a morphism between those.
Jan 10 at 11:22 history edited ett CC BY-SA 4.0
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Jan 10 at 11:18 comment added abx Sorry, I thought you were asking about $H^0$. I don't think Bott's theorem tells you anything about $H^m$ (or $H^0$, for that matter).
Jan 10 at 10:49 comment added ett We know how it acts on the global sections, but I am not sure how to translate this to higher cohomologies. I know how to understand what $H^m(\bigwedge^i\mathcal E^\ast)$ is via Bott's theorem, but I cannot see how to translate this map, that I know how it works on the global section level, to higher cohomologies.
Jan 10 at 10:38 comment added abx I don't understand the question. The map $\phi_i$ is explicit (interior product with $s$), so don't we know how it acts on global sections?
S Jan 10 at 10:31 review First questions
Jan 10 at 10:33
S Jan 10 at 10:31 history asked ett CC BY-SA 4.0