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Jan 7 at 3:21 comment added shen lixing @BrendanMcKay Thank you, you are right. There is a gap between my "prove".
S Jan 6 at 9:53 review First answers
Jan 6 at 9:57
S Jan 6 at 9:53 history edited Daniele Tampieri CC BY-SA 4.0
Typo corrected
Jan 6 at 9:51 comment added Daniele Tampieri The DOI cannot be resolved: I added a direct link to the cited paper, though it may get "old".
Jan 6 at 9:28 history edited Daniele Tampieri CC BY-SA 4.0
Minor Math Jaxing and formatting
Jan 6 at 1:54 comment added Brendan McKay Is $M$ a matrix with every element equal to $m$? If so your claim fails for every pair of graphs that are cospectral with cospectral complements. There are many such pairs, for example any pair of cospectral regular graphs.
Jan 6 at 1:41 review Low quality posts
Jan 6 at 9:28
S Jan 6 at 0:54 review First answers
Jan 6 at 1:33
S Jan 6 at 0:54 history answered shen lixing CC BY-SA 4.0