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Jan 10 at 20:17 vote accept SnowRabbit
Jan 5 at 1:58 history edited Michael Hardy CC BY-SA 4.0
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Jan 4 at 18:33 comment added fedja @GiorgioMetafune For you I can tell it in a couple of lines. $PQP$ is a self-adjoint compact (HS) positive definite operator of norm at most $1$. The eigenvalue $1$ is impossible because the eigenvector would be a function with bounded support and spectrum simultaneously. Hence, the norm is strictly less than $1$. If you are interested in quantitative bounds, look at the book by Havin and Joricke "The Uncertainty Principle in Harmonic Analysis" for proofs and references.
Jan 4 at 18:23 comment added Giorgio Metafune Everything is very nice. Where is a proof of the contractivity of $PQ$ for long intervals?
Jan 4 at 17:51 history edited fedja CC BY-SA 4.0
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Jan 4 at 17:08 comment added Christian Remling This is too funny!! As I was writing my comment on your answer to the other question, I was thinking to myself, this question here is probably of that type too... (and I hadn't seen your answer here yet)
Jan 4 at 17:06 comment added fedja @AlekseiKulikov OK. Yeah, for short intervals it is a trivial HS-norm bound. I'll add it a bit later :-)
Jan 4 at 16:36 comment added Aleksei Kulikov Nice argument! I had something quite different and way more technical in mind (cooking a function in the unit disk and then translating it to the upper half-plane). But I think you should give some explanation/reference to the fact that $PQ$ is contractive, while it is quite old I don't think it is that well-known (I assume you have a Hilbert--Schmidt norm argument in mind?)
Jan 4 at 16:19 history answered fedja CC BY-SA 4.0