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Nov 16, 2010 at 12:31 vote accept Martin Brandenburg
Nov 15, 2010 at 21:41 history edited Torsten Ekedahl CC BY-SA 2.5
Added complete proof; deleted 2 characters in body
Nov 15, 2010 at 20:28 comment added Kevin Buzzard Aah---I see what I'm missing---the word "directed" :-) Very nice!
Nov 15, 2010 at 20:23 comment added Kevin Buzzard I am totally confused. Let $V$ be a 2-dimensional vector space. Let $M$ and $P1$ and $P2$ be distinct one-dimensional subspaces. Then $V=P1+P2$ but $M$ is not $(M\cap P1)+(M\cap P2)$. What am I missing?
Nov 15, 2010 at 20:19 comment added Torsten Ekedahl That's exactly the Ab5 axiom.
Nov 15, 2010 at 20:17 comment added Kevin Buzzard Stupid question: how did you interchange the sum and the intersection with $M'$?
Nov 15, 2010 at 20:15 history answered Torsten Ekedahl CC BY-SA 2.5