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Jan 15 at 15:49 history edited Fedor Petrov CC BY-SA 4.0
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Dec 27, 2023 at 9:45 history edited Fedor Petrov CC BY-SA 4.0
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Dec 27, 2023 at 9:32 history edited Fedor Petrov CC BY-SA 4.0
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Dec 27, 2023 at 9:14 vote accept user139952
Dec 27, 2023 at 9:00 comment added Fedor Petrov I say that it is correct. There are $2^{n-3}$ partitions of the three our submultisets onto pairs ($n$ is the total number of elements), each corresponds to at least 6 combinations with total sum at least $s$.
Dec 27, 2023 at 8:57 comment added Daniel Weber I don't understand this answer. Are you saying the statement is wrong? Could you give a concrete example with numbers? Note that you don't have to take one number from each partition, you can take any subset.
Dec 27, 2023 at 8:48 history answered Fedor Petrov CC BY-SA 4.0